Assigning Oxidation States in Compounds
Oxidation states are important for understanding redox reactions. To assign oxidation states, follow these rules:
- Elemental state: The oxidation state of an element in its pure form is 0.
- Monatomic ions: The oxidation state is equal to the charge of the ion. For example, Na^+ has an oxidation state of +1.
- Oxygen: Usually has an oxidation state of -2, except in peroxides where it is -1.
- Hydrogen: Generally has an oxidation state of +1, except when bonded to metals, where it is -1.
- Sum of oxidation states: In a neutral compound, the sum of oxidation states equals 0. In a polyatomic ion, it equals the ion's charge.
For example, in H₂O:
- Hydrogen (H) = +1 (2 H atoms contribute +2)
- Oxygen (O) = -2
- Total = +2 + (-2) = 0, confirming the compound is neutral.
In SO₄²⁻:
- Let sulfur (S) be x. Oxygen = -2 (4 O atoms contribute -8)
- x + (-8) = -2 → x = +6, so S has an oxidation state of +6.
Key points to remember
- Oxidation state of an element in pure form is 0.
- Monatomic ion's oxidation state equals its charge.
- Oxygen usually has an oxidation state of -2.
- In compounds, the total oxidation states equal 0.
- In ions, the total equals the ion's charge.
Worked example
Assign oxidation states in NaCl: Na = +1, Cl = -1; Total = +1 + (-1) = 0.