Three-dimensional geometry — KCSE Mathematics

KCSE Mathematics · 101 practice questions · 3 syllabus objectives · 3 revision lessons

28 easy37 medium36 hard

Last updated · Aligned to the KNEC KCSE syllabus

What You'll Learn

Key learning outcomes for this topic, aligned to the KNEC KCSE syllabus.

State the geometric properties of common solids and identify skew lines

Calculate the length between two points in three-dimensional geometry

Calculate the angle between two lines, a line and a plane, and two planes

Revision Notes

Concise lesson notes for Three-dimensional geometry, written to the KCSE Mathematics marking standard. Read the first lesson free below.

Properties of Common Solids and Skew Lines

In three-dimensional geometry, understanding the properties of common solids is essential. Common solids include cubes, spheres, cylinders, and cones. Here are their geometric properties:

  • Cube: 6 faces (all squares), 12 edges, 8 vertices.
  • Sphere: No edges or vertices, one curved surface.
  • Cylinder: 2 circular faces, 1 curved surface, 2 edges, 0 vertices.
  • Cone: 1 circular face, 1 vertex, 1 curved surface, 1 edge.

Skew lines are lines that do not intersect and are not parallel. They exist in different planes. For example, consider lines AB and CD in space where:

  • Line AB is on the plane of the cube.
  • Line CD passes through the cylinder.

These lines do not meet and are not parallel, hence they are skew lines. Identifying skew lines involves visualizing or sketching the 3D arrangement of the lines and solids involved.

Key points to remember

  • Cubes have 6 faces, 12 edges, and 8 vertices.
  • Spheres have one curved surface and no edges or vertices.
  • Cylinders have 2 circular faces and 1 curved surface.
  • Cones have 1 circular face and 1 vertex.
  • Skew lines do not intersect and are not parallel.

Worked example

Identify the skew lines in the following scenario: Lines PQ and RS do not meet and are in different planes. Answer: Lines PQ and RS are skew lines as they do not intersect and are not parallel.

Read all 3 Three-dimensional geometry lessons free

Sign up free to unlock the full set of revision notes, all 101 practice questions with marking schemes, plus a personalised study plan that adapts to the topics you keep getting wrong.

More lessons in this topic

Lesson 2: Calculating Distance in 3D Geometry

Objective: Calculate the length between two points in three-dimensional geometry

In three-dimensional geometry, the distance between two points can be calculated using the distance formula. Given two points, A(x₁, y₁, z₁) and B(x₂, y₂, z₂), the distance d between them is given by the formula:

d = √((x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)²).

Steps to Calculate Distance:

  1. Identify the coordinates of the two points.
  2. Substitute the coordinates into the distance formula.
  3. Simplify the expression under the square root.
  4. Calculate the square root to find the distance.

Example:

Calculate the distance between points A(1, 2, 3) and B(4, 6, 8).

  1. Identify coordinates: A(1, 2, 3), B(4, 6, 8).
  2. Substitute: d = √((4 - 1)² + (6 - 2)² + (8 - 3)²).
  3. Simplify: d = √(3² + 4² + 5²) = √(9 + 16 + 25).
  4. Calculate: d = √50 = 5√2.

Thus, the distance between points A and B is 5√2 units.

  • Use the distance formula for 3D points.
  • Identify coordinates clearly before calculation.
  • Simplify expressions under the square root accurately.
  • Calculate the final distance carefully.

Calculate the distance between points P(2, 3, 5) and Q(6, 7, 9).

  1. d = √((6 - 2)² + (7 - 3)² + (9 - 5)²) = √(16 + 16 + 16) = √48 = 4√3.
Lesson 3: Calculating Angles in 3D Geometry

Objective: Calculate the angle between two lines, a line and a plane, and two planes

In three-dimensional geometry, calculating angles is essential for understanding spatial relationships. To find the angle between two lines, use the direction ratios of the lines. For a line and a plane, apply the formula:

Angle (θ) = cos⁻¹((d1 · n) / (|d1| |n|))
where:

  • d1 is the direction ratio of the line
  • n is the normal vector of the plane
  • · denotes the dot product
  • | | denotes magnitude

To find the angle between two planes, use their normal vectors. The formula is similar:

Angle (φ) = cos⁻¹((n1 · n2) / (|n1| |n2|))
where n1 and n2 are the normal vectors of the planes.

It is important to ensure that all vectors are defined correctly and that you calculate the dot product accurately.

  • Use direction ratios to find the angle between two lines.
  • Apply the angle formula for a line and a plane.
  • Use normal vectors to find the angle between two planes.
  • Ensure correct calculation of dot products and magnitudes.
  • Angles are measured in degrees or radians.

Calculate the angle between lines with direction ratios (1, 2, 3) and (4, 5, 6).
Model Answer:

  • Find dot product: (14 + 25 + 3*6) = 32
  • Find magnitudes: |(1, 2, 3)| = √14, |(4, 5, 6)| = √77
  • Angle θ = cos⁻¹(32 / (√14 * √77))

Sample Questions

Read 3 questions and answers free. Sign up to access all 101 questions with full KNEC-style marking schemes and a personalised study plan.

1
easySHORT ANSWER3 marks

Given the line defined by the direction ratios (2, -3, 1) and the plane given by the equation 3x + 4y - 2z = 12, calculate the angle between the line and the plane. (3 marks)

Answer & marking scheme

Part (a) — 3 marks
Normal vector of the plane = (3, 4, -2) (1 mk)
Dot product = 2*3 + (-3)*4 + 1*(-2) (1 mk)
Use formula cos θ = (|dot product|)/(magnitude of line * magnitude of normal) (1 mk)
2
easySHORT ANSWER3 marks

Given points P(1, 2, 3) and Q(4, 6, 8), find the distance PQ in three-dimensional space. (3 marks)

Answer & marking scheme

Part (b) — 3 marks
PQ = √((4 - 1)² + (6 - 2)² + (8 - 3)²) (1 mk)
PQ = √(3² + 4² + 5²) (1 mk)
PQ = √(9 + 16 + 25) = √50 (1 mk)
3
easySHORT ANSWER3 marks

The coordinates of points A and B are (2, 3, 5) and (4, 7, 1) respectively. Calculate the length of the line segment AB. (3 marks)

Answer & marking scheme

Part (a) — 3 marks
AB = √((4 - 2)² + (7 - 3)² + (1 - 5)²) (1 mk)
AB = √(2² + 4² + (-4)²) (1 mk)
AB = √(4 + 16 + 16) = √36 (1 mk)
4

Identify two pairs of skew lines from the edges of a rectangular prism with vertices A, B, C, D, E, F, G, and H. (2 marks)

+98 More Questions

Sign up free to access all 101 questions with marking schemes, track your progress, and get personalised recommendations.

Frequently asked questions

What does the KCSE Mathematics topic "Three-dimensional geometry" cover?

Properties of common solids; skew lines; projection of a line onto a plane; angles between lines and planes

How many practice questions are available for Three-dimensional geometry?

HighMarks has 101 Three-dimensional geometry practice questions for KCSE Mathematics, each with a full marking scheme. The first 3 are free; sign up to access the rest, plus all KCSE mock exams and past papers.

Are these aligned with the KNEC KCSE syllabus?

Yes. Every objective on this page is taken directly from the official KNEC KCSE Mathematics syllabus. Practice questions match the KCSE exam format and are graded against the standard KNEC marking scheme.

How should I revise Three-dimensional geometry for the KCSE exam?

Start with the revision notes on this page to refresh the core concepts, then work through the practice questions in increasing difficulty. Sign up for HighMarks to get a personalised study plan that adapts to the topics you keep getting wrong, plus mock exams, subject-wide practice, and detailed performance tracking. See pricing.

Why Practise Three-dimensional geometry?

KNEC Aligned

Questions match the KCSE syllabus objectives and exam format exactly.

Detailed Marking Schemes

Every answer shows exactly what examiners award marks for.

Track Your Mastery

See your score improve as you practise and identify remaining gaps.

Master Three-dimensional geometry for KCSE

Sign up free to unlock all 101 questions, track your progress, and get a personalised study plan for Mathematics.