Trigonometry: sine rule — KCSE Mathematics

KCSE Mathematics · 100 practice questions · 3 syllabus objectives · 3 revision lessons

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Last updated · Aligned to the KNEC KCSE syllabus

What You'll Learn

Key learning outcomes for this topic, aligned to the KNEC KCSE syllabus.

State the sine rule: a/sin A = b/sin B = c/sin C, and identify when to apply it (given AAS, ASA or SSA)

Apply the sine rule to find unknown sides and angles in non-right-angled triangles; handle the ambiguous case

Trigonometry: sine rule

Revision Notes

Concise lesson notes for Trigonometry: sine rule, written to the KCSE Mathematics marking standard. Read the first lesson free below.

Understanding the Sine Rule

The sine rule states that for any triangle with sides a, b, and c opposite to angles A, B, and C respectively, the relationship can be expressed as:
a/sin A = b/sin B = c/sin C.
This rule is particularly useful when solving triangles in the following scenarios:

  • AAS (Angle-Angle-Side): When you know two angles and one side.
  • ASA (Angle-Side-Angle): When you know one side and the two angles adjacent to it.
  • SSA (Side-Side-Angle): When you know two sides and a non-included angle.
    In these cases, you can use the sine rule to find unknown sides or angles. Remember that SSA can sometimes lead to ambiguous cases, so always check your results.
    For example, in triangle ABC, if A = 30°, B = 45°, and a = 10 cm, we can find side b using the sine rule.

Key points to remember

  • Sine rule: a/sin A = b/sin B = c/sin C.
  • Apply when given AAS, ASA, or SSA.
  • Useful for finding unknown sides or angles.
  • Check for ambiguous cases in SSA.
  • Always ensure angles are in the same triangle.

Worked example

Given triangle ABC with A = 30°, B = 45°, and a = 10 cm, find side b.
Using sine rule:
b/sin B = a/sin A
b = a * (sin B / sin A)
b = 10 * (sin 45° / sin 30°)
b = 10 * (√2/2 / 1/2)
b = 10 * √2
b ≈ 14.14 cm.

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More lessons in this topic

Lesson 2: Applying the Sine Rule in Triangles

Objective: Apply the sine rule to find unknown sides and angles in non-right-angled triangles; handle the ambiguous case

The sine rule is a crucial tool for solving non-right-angled triangles. It states that the ratio of a side of a triangle to the sine of its opposite angle is constant. The formula is given as:

a/sin(A) = b/sin(B) = c/sin(C)

where:

  • a, b, c are the lengths of the sides,
  • A, B, C are the angles opposite those sides.

Steps to Apply the Sine Rule:

  1. Identify the known sides and angles in the triangle.
  2. Use the sine rule to find the unknown side or angle.
  3. If you encounter an ambiguous case (two possible angles), evaluate both scenarios.

Example:

Given triangle ABC, where angle A = 30°, side a = 10 cm, and side b = 15 cm, find angle B.

Using the sine rule:

  • a/sin(A) = b/sin(B)
  • 10/sin(30°) = 15/sin(B)
  • 10/0.5 = 15/sin(B)
  • 20 = 15/sin(B)
  • sin(B) = 15/20 = 0.75
  • Therefore, B = sin⁻¹(0.75) ≈ 48.6°.

Check for the ambiguous case:

  • The second possible angle B' = 180° - 48.6° = 131.4°.

Thus, the possible angles for B are 48.6° or 131.4°.

  • Sine rule applies to non-right-angled triangles.
  • Formula: a/sin(A) = b/sin(B) = c/sin(C).
  • Identify known sides and angles before applying.
  • Handle ambiguous cases by calculating both possible angles.
  • Always check if the triangle is valid with the calculated angles.

Given triangle ABC, where A = 40°, a = 8 cm, and b = 10 cm, find angle B. Using sine rule: 8/sin(40°) = 10/sin(B) → sin(B) = 10 * sin(40°)/8 → B ≈ 60.3°.

Lesson 3: Understanding the Sine Rule in Trigonometry

Objective: Trigonometry: sine rule

The sine rule relates the sides and angles of a triangle. It states that in any triangle, the ratio of a side length to the sine of its opposite angle is constant. This can be expressed as:

a/sin(A) = b/sin(B) = c/sin(C)

Where:

  • a, b, c are the lengths of the sides.
  • A, B, C are the angles opposite those sides.

The sine rule is particularly useful for solving triangles when:

  • You know two angles and one side (AAS or ASA).
  • You know two sides and a non-included angle (SSA).

To apply the sine rule, follow these steps:

  1. Identify the known sides and angles.
  2. Set up the sine rule equation.
  3. Solve for the unknown side or angle.

Example: In triangle ABC, if angle A = 30° and angle B = 45°, and side a = 10 cm, find side b.

  • First, find angle C: C = 180° - (30° + 45°) = 105°.

  • Apply the sine rule:

    ( \frac{a}{\sin(A)} = \frac{b}{\sin(B)} )
    ( \frac{10}{\sin(30°)} = \frac{b}{\sin(45°)} )
    ( b = \frac{10 \cdot \sin(45°)}{\sin(30°)} )
    ( b = 10 \cdot \frac{\sqrt{2}/2}{1/2} = 10\sqrt{2} )

Thus, side b is approximately 14.14 cm.

  • Sine rule relates sides and angles in triangles.
  • Formula: a/sin(A) = b/sin(B) = c/sin(C).
  • Useful for AAS, ASA, or SSA triangle configurations.
  • Find unknowns by setting up the sine rule equation.
  • Ensure angles are in the same unit before calculations.

In triangle ABC, A = 40°, B = 60°, a = 12 cm. Find b.

  • C = 180° - (40° + 60°) = 80°.
  • ( \frac{12}{\sin(40°)} = \frac{b}{\sin(60°)} )
  • ( b = \frac{12 \cdot \sin(60°)}{\sin(40°)} \approx 14.11 ).

Sample Questions

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1
easySHORT ANSWER4 marks

State the steps to find the length of side c in triangle XYZ, where angle X = 45°, angle Y = 60°, and side y = 9 cm. Justify whether the sine rule can be applied in this scenario. (4 marks)

Answer & marking scheme

Part (a) — 3 marks
Calculate angle Z using the fact that the angles in a triangle sum to 180° (1 mk)
Use the sine rule: y/sin(Y) = c/sin(C) (1 mk)
Substitute the known values and solve for c (1 mk)
Part (b) — 1 mark
Yes, the sine rule can be applied as two angles and a side are known (1 mk)
2
easySHORT ANSWER3 marks

Explain how to determine the angle opposite side a in triangle ABC, where side a = 8 cm, side b = 10 cm, and angle B = 30°. Discuss if there is a possibility of more than one solution for angle A. (3 marks)

Answer & marking scheme

Part (a) — 2 marks
Use the sine rule: a/sin(A) = b/sin(B) (1 mk)
Substitute values and solve for sin(A) (1 mk)
Part (b) — 1 mark
Yes, there could be two possible angles for A due to the sine function (1 mk)
3
easySHORT ANSWER4 marks

State the sine rule and identify two specific cases where it can be applied in triangle XYZ. (4 marks)

Answer & marking scheme

Part (a) — 1 mark
a/sin A = b/sin B = c/sin C (or equivalent reciprocal form) (1 mk)
Part (b) — 3 marks
AAS (Angle-Angle-Side) (1 mk)
ASA (Angle-Side-Angle) (1 mk)
SSA (Side-Side-Angle) (1 mk)
4

State the sine rule and explain when it is applicable in triangle ABC. (3 marks)

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Frequently asked questions

What does the KCSE Mathematics topic "Trigonometry: sine rule" cover?

Trigonometry: sine rule covers State the sine rule: a/sin A = b/sin B = c/sin C, and identify when to apply it (given AAS, ASA or SSA); Apply the sine rule to find unknown sides and angles in non-right-angled triangles; handle the ambiguous case; Trigonometry: sine rule, all aligned to the official KNEC KCSE Mathematics syllabus.

How many practice questions are available for Trigonometry: sine rule?

HighMarks has 100 Trigonometry: sine rule practice questions for KCSE Mathematics, each with a full marking scheme. The first 3 are free; sign up to access the rest, plus all KCSE mock exams and past papers.

Are these aligned with the KNEC KCSE syllabus?

Yes. Every objective on this page is taken directly from the official KNEC KCSE Mathematics syllabus. Practice questions match the KCSE exam format and are graded against the standard KNEC marking scheme.

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