Photoelectric effect — KCSE Physics

KCSE Physics · 106 practice questions · 4 syllabus objectives · 4 revision lessons

29 easy40 medium37 hard

Last updated · Aligned to the KNEC KCSE syllabus

What You'll Learn

Key learning outcomes for this topic, aligned to the KNEC KCSE syllabus.

Describe experiments to illustrate photoelectric effect and explain factors affecting it

Define threshold frequency, work function and electron volt and apply E = hf

Explain photoelectric emission using Einstein's equation and describe applications

Calculate photon energy, maximum kinetic energy, stopping potential and velocity of photoelectrons

Revision Notes

Concise lesson notes for Photoelectric effect, written to the KCSE Physics marking standard. Read the first lesson free below.

Understanding the Photoelectric Effect

The photoelectric effect is a phenomenon where electrons are emitted from a material when it absorbs light. Key experiments illustrating this effect include:

  • Einstein’s Experiment: When light shines on a metal surface, it can cause the emission of electrons. The intensity and frequency of light influence this emission.
  • Threshold Frequency: Each material has a specific frequency (threshold frequency) below which no electrons are emitted, regardless of light intensity.

Factors affecting the photoelectric effect include:

  • Light Frequency: Higher frequency light (e.g., ultraviolet) can emit electrons, while lower frequency light (e.g., red) may not.
  • Light Intensity: Increasing intensity increases the number of emitted electrons, but only if the light frequency is above the threshold.
  • Type of Material: Different materials have different work functions, affecting the ease of electron emission.

In summary, the photoelectric effect demonstrates the particle nature of light and is crucial for understanding quantum physics.

Key points to remember

  • Photoelectric effect involves electron emission from materials upon light exposure.
  • Threshold frequency is essential; below it, no electrons are emitted.
  • Higher light frequency increases electron emission probability.
  • Increased light intensity raises the number of emitted electrons.
  • Different materials have varying work functions affecting emission.

Worked example

Describe an experiment demonstrating the photoelectric effect.

  • Shine ultraviolet light on a clean metal surface.
  • Observe the emission of electrons, confirming light's particle nature.

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Lesson 2: Understanding Key Concepts in Photoelectric Effect

Objective: Define threshold frequency, work function and electron volt and apply E = hf

In the photoelectric effect, certain key terms are essential to grasp:

  • Threshold Frequency (f0): This is the minimum frequency of incident light required to eject electrons from a metal surface. If the frequency is below this threshold, no electrons will be emitted, regardless of light intensity.

  • Work Function (Φ): This is the minimum energy needed to remove an electron from the surface of the metal. It is usually measured in electron volts (eV). The work function is related to the threshold frequency by the equation:

    [ \Phi = h f_0 ]

    where ( h ) is Planck's constant (6.63 x 10-34 J·s).

  • Electron Volt (eV): This is a unit of energy equal to the amount of kinetic energy gained by an electron when it is accelerated through a potential difference of one volt. 1 eV = 1.6 x 10-19 Joules.

To find the energy of a photon, use the formula:

[ E = hf ]

where ( E ) is the energy, ( h ) is Planck's constant, and ( f ) is the frequency of the light.

  • Threshold frequency is the minimum frequency to eject electrons.
  • Work function is the energy needed to remove an electron.
  • 1 eV equals 1.6 x 10^-19 Joules.
  • Energy of a photon is calculated using E = hf.

Define threshold frequency and work function.

  • Threshold frequency (f0) is the minimum frequency to eject electrons.
  • Work function (Φ) is the minimum energy required to remove an electron from the metal surface.
Lesson 3: Understanding the Photoelectric Effect

Objective: Explain photoelectric emission using Einstein's equation and describe applications

The photoelectric effect occurs when light shines on a metal surface, causing the emission of electrons. Einstein's equation, E = hf - W, explains this phenomenon:

  • E is the kinetic energy of the emitted electrons.
  • h is Planck's constant (6.63 x 10^-34 Js).
  • f is the frequency of the incident light.
  • W is the work function of the metal, the minimum energy needed to release an electron.

When light of sufficient frequency strikes the metal, it transfers energy to the electrons. If the energy exceeds the work function, electrons are emitted with kinetic energy equal to the difference between the photon energy and the work function.

Applications of the photoelectric effect include:

  • Photoelectric cells in solar panels convert sunlight into electricity.
  • Photodetectors in cameras that adjust exposure based on light levels.
  • Electron microscopes that utilize emitted electrons for high-resolution imaging.
  • Photoelectric effect involves emission of electrons from metals.
  • Einstein's equation relates energy, frequency, and work function.
  • Electrons are emitted if light frequency exceeds a threshold.
  • Applications include solar panels and photodetectors.
  • Kinetic energy of emitted electrons is E = hf - W.

Explain the photoelectric effect using Einstein's equation.

  • The photoelectric effect occurs when light causes electron emission from a metal.
  • Einstein's equation E = hf - W describes this process, where E is kinetic energy.
Lesson 4: Understanding the Photoelectric Effect Calculations

Objective: Calculate photon energy, maximum kinetic energy, stopping potential and velocity of photoelectrons

The photoelectric effect demonstrates how light can eject electrons from a material. To solve problems related to this effect, you need to calculate:

  1. Photon Energy (E): Use the formula:
    [ E = hf ]
    where ( h ) is Planck's constant (6.63 × 10⁻³⁴ J·s) and ( f ) is the frequency of light.

  2. Maximum Kinetic Energy (K.E.): This is given by:
    [ K.E. = E - \phi ]
    where ( \phi ) is the work function of the material.

  3. Stopping Potential (V_s): It is calculated using:
    [ V_s = \frac{K.E.}{e} ]
    where ( e ) is the charge of an electron (1.6 × 10⁻¹⁹ C).

  4. Velocity of Photoelectrons (v): Use the formula:
    [ v = \sqrt{\frac{2K.E.}{m}} ]
    where ( m ) is the mass of an electron (9.11 × 10⁻³¹ kg).

By applying these formulas, you can solve various problems related to the photoelectric effect effectively.

  • Photon energy is calculated using E = hf.
  • Maximum kinetic energy is K.E. = E - φ.
  • Stopping potential is V_s = K.E. / e.
  • Velocity of photoelectrons is v = √(2K.E. / m).

A photon with a frequency of 6 × 10¹⁴ Hz strikes a metal surface with a work function of 2.5 eV. Calculate the photon energy and maximum kinetic energy of the emitted electrons.

  • Photon energy, E = hf = (6.63 × 10⁻³⁴ J·s)(6 × 10¹⁴ Hz) = 3.98 × 10⁻¹⁹ J (convert to eV: 2.48 eV).
  • Maximum K.E. = E - φ = 2.48 eV - 2.5 eV = 0 eV (no electrons emitted).

Sample Questions

Read 3 questions and answers free. Sign up to access all 106 questions with full KNEC-style marking schemes and a personalised study plan.

1
easySHORT ANSWER4 marks

Define the term 'work function' and describe its significance in the context of the photoelectric effect. (4 marks)

Answer & marking scheme

Part (a) — 1 mark
The minimum energy required to remove an electron from the surface of a material (1 mk)
Part (b) — 3 marks
Determines whether photoelectric emission will occur depending on the energy of incoming photons (1 mk)
Affects the threshold frequency of light needed for emission (1 mk)
Different materials have different work functions, influencing their photoelectric properties (1 mk)
2
easySHORT ANSWER4 marks

Explain how Einstein's equation relates to the photoelectric effect. (4 marks)

Answer & marking scheme

Part (a) — 1 mark
E = hf - φ (where E is the energy of the emitted electron, hf is the energy of the photon, and φ is the work function) (1 mk)
Part (b) — 3 marks
E is the maximum kinetic energy of the emitted electrons (1 mk)
hf is the energy of the incident photon, determined by its frequency (1 mk)
φ is the minimum energy required to release an electron from the material (1 mk)
3
easySHORT ANSWER3 marks

Define the photoelectric effect and give two examples of its applications in modern technology. (3 marks)

Answer & marking scheme

Part (a) — 1 mark
The emission of electrons from a material when it absorbs light energy (1 mk)
Part (b) — 2 marks
Photovoltaic cells for solar energy conversion (1 mk)
Photoelectric sensors in automatic doors (1 mk)
4

Define the term 'work function' in the context of the photoelectric effect and describe its importance in determining if photoemission will occur. (4 marks)

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Frequently asked questions

What does the KCSE Physics topic "Photoelectric effect" cover?

Photons, threshold frequency, work function, Einstein's equation, applications

How many practice questions are available for Photoelectric effect?

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Are these aligned with the KNEC KCSE syllabus?

Yes. Every objective on this page is taken directly from the official KNEC KCSE Physics syllabus. Practice questions match the KCSE exam format and are graded against the standard KNEC marking scheme.

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