Quantity of heat — KCSE Physics

KCSE Physics · 116 practice questions · 6 syllabus objectives · 6 revision lessons

36 easy41 medium39 hard

Last updated · Aligned to the KNEC KCSE syllabus

What You'll Learn

Key learning outcomes for this topic, aligned to the KNEC KCSE syllabus.

Define heat capacity and specific heat capacity and determine them experimentally

Define specific latent heat of fusion and vaporisation and determine them experimentally

State factors affecting melting and boiling points and solve problems involving Q = mcΔT and Q = mL

Explain the functioning of a pressure cooker and a refrigerator

Interpret heating and cooling curves; explain temperature plateaus during phase changes

Solve numerical problems involving heat exchange, method of mixtures, and calorimetry

Revision Notes

Concise lesson notes for Quantity of heat, written to the KCSE Physics marking standard. Read the first lesson free below.

Understanding Heat Capacity and Specific Heat Capacity

Heat capacity is defined as the amount of heat required to raise the temperature of an object by 1 degree Celsius (°C). It is an extensive property, meaning it depends on the mass of the substance. The formula for heat capacity (C) is:

C = Q / ΔT

where Q is the heat added and ΔT is the change in temperature.

Specific heat capacity (c) is the amount of heat required to raise the temperature of 1 kilogram of a substance by 1°C. It is an intensive property, independent of mass. The formula for specific heat capacity is:

c = Q / (m × ΔT)

where m is the mass of the substance.

To determine heat capacity and specific heat capacity experimentally, you can conduct a simple experiment using a calorimeter. Measure the mass of the substance, heat it with a known quantity of heat (Q), and measure the temperature change (ΔT). Then apply the formulas above to calculate both capacities.

Key points to remember

  • Heat capacity is the heat needed to raise temperature by 1°C.
  • Specific heat capacity is heat needed for 1 kg to change by 1°C.
  • Heat capacity is extensive; specific heat capacity is intensive.
  • Use calorimeter for experimental determination of capacities.
  • Formulas: C = Q / ΔT, c = Q / (m × ΔT).

Worked example

Define heat capacity and specific heat capacity.

  • Heat capacity is the heat needed to increase temperature by 1°C.
  • Specific heat capacity is the heat needed to raise 1 kg by 1°C.

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Lesson 2: Understanding Specific Latent Heat

Objective: Define specific latent heat of fusion and vaporisation and determine them experimentally

Specific latent heat is the amount of heat required to change the state of a unit mass of a substance without changing its temperature. There are two types:

  • Latent heat of fusion: This is the heat required to convert a unit mass of solid into liquid at its melting point.
  • Latent heat of vaporisation: This is the heat required to convert a unit mass of liquid into gas at its boiling point.

To determine these values experimentally, you can use the following methods:

  1. For latent heat of fusion: Measure the mass of ice being melted. Heat the ice using a calorimeter and record the heat supplied until all ice melts. Use the formula:

    [ L_f = \frac{Q}{m} ]

    where ( L_f ) is the latent heat of fusion, ( Q ) is the heat supplied, and ( m ) is the mass of ice.

  2. For latent heat of vaporisation: Similarly, measure the mass of water being vaporised. Heat the water until it completely converts to steam. Use the formula:

    [ L_v = \frac{Q}{m} ]

    where ( L_v ) is the latent heat of vaporisation, ( Q ) is the heat supplied, and ( m ) is the mass of water.

  • Specific latent heat changes state without temperature change.
  • Latent heat of fusion relates to solid to liquid change.
  • Latent heat of vaporisation relates to liquid to gas change.
  • Use calorimetry to measure heat changes accurately.
  • Apply formulas to calculate latent heats effectively.

Define specific latent heat of fusion. \nSpecific latent heat of fusion is the heat required to convert 1 kg of solid into liquid at its melting point without temperature change.

Lesson 3: Factors Affecting Melting and Boiling Points

Objective: State factors affecting melting and boiling points and solve problems involving Q = mcΔT and Q = mL

The melting and boiling points of substances are influenced by several factors:

  • Intermolecular Forces: Stronger forces lead to higher melting and boiling points.
  • Molecular Weight: Heavier molecules generally have higher melting and boiling points.
  • Pressure: Increasing pressure raises boiling points, particularly for liquids.
  • Impurities: The presence of impurities can lower melting points (freezing point depression) and affect boiling points.

To solve problems involving heat transfer, we use the formulas:

  • Q = mcΔT: This calculates the heat (Q) absorbed or released when a substance changes temperature, where:

    • m = mass (kg)
    • c = specific heat capacity (J/kg°C)
    • ΔT = change in temperature (°C)
  • Q = mL: This calculates the heat (Q) involved in phase changes, where:

    • L = latent heat (J/kg)

Understanding these concepts is crucial for solving related problems effectively.

  • Intermolecular forces affect melting and boiling points significantly.
  • Higher molecular weight typically results in higher melting and boiling points.
  • Increased pressure raises the boiling point of liquids.
  • Impurities can lower melting points and alter boiling points.
  • Use Q = mcΔT and Q = mL for heat calculations.

Calculate the heat required to raise the temperature of 2 kg of water from 20°C to 80°C. Given c = 4,200 J/kg°C.

Answer:

  • m = 2 kg
  • c = 4,200 J/kg°C
  • ΔT = 80°C - 20°C = 60°C
  • Q = mcΔT = 2 kg × 4,200 J/kg°C × 60°C = 504,000 J.
Lesson 4: Understanding Pressure Cookers and Refrigerators

Objective: Explain the functioning of a pressure cooker and a refrigerator

A pressure cooker functions by increasing the pressure inside the cooking chamber. This increased pressure raises the boiling point of water, allowing food to cook faster. The cooker has a sealed lid with a valve that regulates the steam pressure. When the pressure reaches a certain level, the valve releases excess steam to maintain safe cooking conditions. This efficient heat transfer results in quicker cooking times.

On the other hand, a refrigerator operates using the principles of evaporation and condensation. It contains a refrigerant that absorbs heat from the interior as it evaporates in the evaporator coils. The compressor then compresses this gas, raising its pressure and temperature. This hot gas moves to the condenser coils, where it releases heat to the surroundings and condenses back into a liquid. This cycle continues, keeping the inside of the refrigerator cool by removing heat from the stored items.

  • Pressure cookers increase pressure to raise boiling point of water.
  • Refrigerators use evaporation and condensation to cool interiors.
  • Heat transfer in pressure cookers speeds up cooking.
  • Refrigerators maintain low temperatures by removing heat.

Explain how a pressure cooker works.

  • Increases pressure inside the chamber.
  • Raises boiling point of water for faster cooking.
  • Steam pressure is regulated by a valve.

Sample Questions

Read 3 questions and answers free. Sign up to access all 116 questions with full KNEC-style marking schemes and a personalised study plan.

1
easySHORT ANSWER2 marks

State the formula used to calculate the heat absorbed by a substance when its temperature changes. (2 marks)

Answer & marking scheme

Part (a) — 2 marks
Q = mcΔT (1 mk)
Where Q is the heat absorbed, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature (1 mk)
2
easySHORT ANSWER3 marks

List three reasons for the temperature plateau observed during the melting of ice. (3 marks)

Answer & marking scheme

Part (a) — 3 marks
Heat energy is absorbed to break the bonds between ice molecules (1 mk)
Temperature remains constant as the phase change occurs (1 mk)
All added heat is used for melting rather than increasing temperature (1 mk)
3
easySHORT ANSWER2 marks

Identify two ways in which a pressure cooker increases the temperature of the boiling water. (2 marks)

Answer & marking scheme

Part (a) — 2 marks
It increases the pressure inside the cooker, raising the boiling point of water above 100°C (1 mk)
It traps steam, which also increases temperature due to the increased pressure (1 mk)
4

State the difference between specific heat capacity and heat capacity. (4 marks)

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Frequently asked questions

What does the KCSE Physics topic "Quantity of heat" cover?

Specific heat capacity, latent heat, boiling/melting points, calorimetry

How many practice questions are available for Quantity of heat?

HighMarks has 116 Quantity of heat practice questions for KCSE Physics, each with a full marking scheme. The first 3 are free; sign up to access the rest, plus all KCSE mock exams and past papers.

Are these aligned with the KNEC KCSE syllabus?

Yes. Every objective on this page is taken directly from the official KNEC KCSE Physics syllabus. Practice questions match the KCSE exam format and are graded against the standard KNEC marking scheme.

How should I revise Quantity of heat for the KCSE exam?

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